12p^2+2p-18=0

Solution for 12p^2+2p-18=0 equation:

12p^2+2p-18=0

a = 12; b = 2; c = -18;
Δ = b2-4ac
Δ = 22-4·12·(-18)
Δ = 868
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{868}=\sqrt{4*217}=\sqrt{4}*\sqrt{217}=2\sqrt{217}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{217}}{2*12}=\frac{-2-2\sqrt{217}}{24}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{217}}{2*12}=\frac{-2+2\sqrt{217}}{24}
$